X^2=25x+54

Solution for X^2=25x+54 equation:

X^2=25X+54

We move all terms to the left:

X^2-(25X+54)=0

We get rid of parentheses

X^2-25X-54=0

a = 1; b = -25; c = -54;
Δ = b2-4ac
Δ = -252-4·1·(-54)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-29}{2*1}=\frac{-4}{2}
=-2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+29}{2*1}=\frac{54}{2}
=27
$